The singer may sing "Same Love" with the rap duo
Yesterday, it was confirmed that Madonna will be making an appearance onstage at the 56th GRAMMYs tomorrow (Jan. 26). Now, in the spirit of intriguing collaborations the ceremony generally provides, it looks like the pop diva could be performing with none other than Macklemore & Ryan Lewis.
According to US Weekly, sources have confirmed to the publication that Madonna will team up with the oft-nominated rap/production duo on its hit "Same Love," pairing the voice within the LBGT community with a song about equality and support of same-sex marriage.
"Same Love," nominated for Song of the Year at the ceremony, generally features a hook performed by Seattle singer-songwriter Mary Lambert, who is herself a lesbian. Lambert is in Los Angeles for the GRAMMYs, meaning Madonna may be an addition rather than a replacement, much like Jennifer Hudson's appearance on the song at the 2013 MTV VMAs.
Macklemore & Ryan Lewis are nominated for seven GRAMMYs this year, including its Song of the Year nod, Album of the Year for "The Heist" and Best New Artist.
The Madonna-Macklemore collaboration will join other already-announced pairings, including Metallica and pianist Lang Lang, a mash-up featuring Dave Grohl, Nine Inch Nails, Lindsey Buckingham and Queens of the Stone Age, plus a hotly-anticipated Daft Punk performance featuring Stevie Wonder, Nile Rodgers and Pharrell.